X^2-5x+41=-15x

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Solution for X^2-5x+41=-15x equation: 



X^2-5X+41=-15X

We move all terms to the left:

X^2-5X+41-(-15X)=0

We get rid of parentheses

X^2-5X+15X+41=0

We add all the numbers together, and all the variables

X^2+10X+41=0

a = 1; b = 10; c = +41;
Δ = b2-4ac
Δ = 102-4·1·41
Δ = -64
Delta is less than zero, so there is no solution for the equation

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